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322 l of hydrogen occupies volume of 197 l at stp. what was the initial pressure exerted on the hydrogen constant

Respuesta :

kenmyna
  The  initial  pressure  exerted   on  the  hydrogen  constant  is  caculated  using the  Boyles law  formula
that is  P1V1=P2V2
P1=  ?
 V1=  322 L
V2=  197 L
P2 =  at  STP  =  760  mm hg
 P1   is therefore  =  P2V2/V1
= 760  mmhg  x  197 L/ 322 L =   464.97  mmhg

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