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16-04-2018
Mathematics

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please help!!!!!!!!!!!!!!!

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Professor1994 Professor1994

16-04-2018

x and y vary inversely:
y=k/x

y=8/3 when x=8
8/3=k/8

Solving for k:
8(8/3)=k
64/3=k
k=64/3

y=k/x
y=(64/3)/x
y=(64/3)(1/x)
y=64/(3x)

when x=4→y=64/(3x)=64/(3(4))→y=16/3

Answer: Second Option y=64/(3x); 16/3

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