[tex]2x^2+12x-14=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2+6x-7=0\\\\x^2+2x\cdot3=7\ \ \ \ |add\ 3^2\ to\ both\ sides\\\\x^2+2x\cdot3+3^2=7+3^2\\\\(x+3)^2=7+9\\\\(x+3)^2=16\iff x+3=-\sqrt{16}\ or\ x+3=\sqrt{16}\\\\x+3=-4\ or\ x+3=4\\\\x=-4-3\ or\ x=4-3\\\\\boxed{x=-7\ or\ x=1}[/tex]