ow many oxygen molecules are in 22.4 liters of oxygen gas at 273k and 101.3kpa First solve the number of moles of the oxygen gas by using the ideal gas equation: PV = nRT Where n is the number of moles n = PV/RT n = (101 300 Pa) (22.4 L) (1 m3/1000 L ) / ( 8.314 Pa m3 / mol K) ( 273 K) n = 1 mol O2 the number of molecules can be solve using avogrados number 6.022x10^23 molecule / mole molecules of one mole O2 = 6.022x 10^23 molecules
