payshencec21
payshencec21
19-03-2018
Mathematics
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PLEASE HELP ASAP!!!!!!!!!!
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taylorellies13
taylorellies13
19-03-2018
i think the answer is c
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WojtekR
WojtekR
19-03-2018
[tex]\dfrac{1}{2^{-2}x^{-3}y^5}=\dfrac{2^2x^3}{y^5}\\\\\\ \dfrac{2^2\cdot2^3}{(-4)^5}=\dfrac{2^5}{(-4)^5}=\left(\dfrac{2}{-4}\right)^5=\left(-\dfrac{1}{2}\right)^5=\boxed{-\dfrac{1}{32}}[/tex]
Answer A)
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