Answer:
Wavelength = 4.0 m
Explanation:
As we know that the distance between first and sixth nodes is given as 10 m
so here between first and sixth node the total number of loops are
N = 5
length of one loop is given by
[tex]\frac{\lambda}{2} = \frac{10}{5}[/tex]
so here we have
[tex]\lambda = 2 \times \frac{10}{5}[/tex]
[tex]\lambda = 4.0 m[/tex]
so the wavelength of the standing wave here is of length 4.0 m
