The transformation maps ΔABC to ΔA'B'C'. Which statement is true about the transformation?

It is isometric because not all side lengths and angle measures remained the same.
It is isometric because all side lengths and angle measures remained the same.
It is not isometric because not all side lengths and angle measures remained the same.
It is not isometric because all side lengths and angle measures remained the sa

The transformation maps ΔABC to ΔABC Which statement is true about the transformation It is isometric because not all side lengths and angle measures remained t class=

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Answer:

B : It is isometric because all side lengths and angle measures remained the same.

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Step-by-step explanation:

EDGE 2021

Ver imagen Kachenium9360

It is isometric because all side lengths and angle measures remained the same.

A transformation is isometric if the transformed image has the same shape has the original image

By careful observation of ΔABC  and  ΔA'B'C':

AC is symmetrical with A'C'

AB  is symmetrical with A'B'

BC is symmetrical with B'C'

<A  is symmetrical with <A'

<B  is symmetrical with <B'

<C is symmetrical with <C'

Since all the sides and angles are symmetrical after transformation, the transformation is isometric

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