Answer:
Standard deviation of ring size is 1.253
Step-by-step explanation:
We are given the following data-set:
12, 10, 11.5, 11.5, 12, 9, 9, 11
n = 8
Formula:
[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]
where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{86}{8} = 10.75[/tex]
Sum of squares of differences = 1.5625 + 0.5625 + 0.5625 + 0.5625 + 1.5625 + 3.0625 + 3.0625 + 0.0625 = 11
[tex]S.D = \sqrt{\displaystyle\frac{11}{7}} = 1.253[/tex]
