Answer:
All the potential root of f(x) are [tex]\pm 1,\pm7, \pm \frac{1}{3},\pm \frac{7}{3}, \pm \frac{1}{9},\pm \frac{7}{9}[/tex].
Step-by-step explanation:
According to the rational root theorem, all the potential root of f(x) are defined as
[tex]x=\pm\frac{p}{q}[/tex]
Where, p is factor of constant term and q is factor of leading coefficient.
The given function is
[tex]f(x)=9x^8+9x^6-12x+7[/tex]
Here, constant term is 7 and leading coefficient is 9.
Factors of 7 are ±1, ±7 and the factors of 9 are ±1, ±3, ±9.
Using rational root theorem, all the potential root of f(x) are
[tex]x=\pm 1,\pm7, \pm \frac{1}{3},\pm \frac{7}{3}, \pm \frac{1}{9},\pm \frac{7}{9}[/tex]
Therefore all the potential root of f(x) are [tex]\pm 1,\pm7, \pm \frac{1}{3},\pm \frac{7}{3}, \pm \frac{1}{9},\pm \frac{7}{9}[/tex].
