Parallel to y = 2x + 7, passes through (3, 11)
Alrighty, so remember : if an equation is parallel to another equation, then both of their slopes are the same.
Identify the slope of our given line. Since our equation is in slope-intercept form, remember that "m" is the slope. Therefore, our slope is 2.
Now, plug in (3, 11) and "m" (2) into slope intercept form, y=mx+b. We're essentially just finding "b" which is our y-intercept.
y = mx+b
(11) = (2)(3) + b
Simplify.
11 = 6 + b
Subtract 6 from both sides.
11 - 6 = b
Therefore, b = 5
So now plug everything into our new equation.
Remember that our new equation has a slope of 2 and a y-intercept of 5.
y = mx+b
y = 2x + 5
~Hope I helped!~
