As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0 K. What is the specific heat capacity of the metal? (1) 0.129 J/g•K (2) 1.95 J/g•K (3) 3.23 J/g•K (4) 7.74 J/g•K

Respuesta :

The formula for the specific heat capacity can be expressed as:

[tex]c = \frac{Q}{m*T} [/tex]

Here,
c = Specific Heat Capacity
Q = Energy absorbed = 48.75 J
m = Mass of the substance = 15.1 gram 
T = Change in temperature = 25 K

Using the values in above formula, we get:

[tex]c = \frac{48.75}{15.1 * 25} = 0.129 J/g.K [/tex]

So the first option 0.129 J/g.K is the correct answer.

The specific heat capacity of the substance is [tex]\rm \bold {0.129J kg^-^1 K^-^1}[/tex].

Specific Heat Capacity:

It is the amount of heat required to increase the temperature of 1 kg substance by 1 Kelvin.

The formula is,

[tex]\rm \bold {c=\frac{Q}{m\times \Delta T} }[/tex]

where,

Q is Energy =48.75 J

m is mass of substance =15.1 g

[tex]\rm \bold {\Delta T}[/tex] is the change in temperature = 25 Kelvin

Put the values,

[tex]\rm \bold {c=\frac{48.75}{15.1\times \ 25} }\\[/tex]

[tex]\rm \bold {c=0.129J kg^-^1 K^-^1}[/tex]

Hence, we can conclude that the specific heat capacity of the substance is [tex]\rm \bold {0.129J kg^-^1 K^-^1}[/tex].

To know more about specific heat capacity, refer tot he link:

https://brainly.com/question/11194034?referrer=searchResults

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