stzayas14
stzayas14
21-01-2018
Mathematics
contestada
Find dy/dx when y = cosh (bx^2}
Pic below
Respuesta :
carlosego
carlosego
21-01-2018
y = cosh (bx^2}
dy/dx= sin
h (bx^2}*( bx^2)'
dy/dx= sinh (bx^2}*( 2bx)
answer
sinh (bx^2}*( 2bx)
Answer Link
VER TODAS LAS RESPUESTAS ( 88+ )
ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE
Otras preguntas
PLZ ANSWER Which statement best describes the effect of replacing the function f(x) = 2x+2 with the function g(x) = 2x-6? The graph shifts 4 units left. The gr
What would happen to an item that is rejected?
What are three main components of magma
graph: y < 1/3x + 1/2
What is my favorite color? Hint: I have two favorites. One color, is a common eye color. The other color is found in Genesis 2:11
Which equation finds the area of a square with a side length of 5n^4 units? (5n^4)^2=25n^8 square units (5n^4)^2=5n^8 square units square units 5( n^4)^2=5n^8
which statement is true about the function f(x) =√-x
what is m4+m5+m6 A. 180 B. 270 C. 300 D. 360
What are some positive affects of the split in America politics in the early 1800s
Factor over the complex numbers: 36x2 + 9.
