Option (A) is correct.
Explanation:
The force of gravity is given by
[tex] F=\frac{G m1 m2}{D^{2}} [/tex]
when distance is made half= d= D/2
[tex] F'=\frac{G m1 m2}{(D/2)^{2}} [/tex]
[tex] F'= 4\frac{G m1 m2}{D^{2}} [/tex]
F'= 4 F
so the force is quadrupled when the distance is D/2
A. D/2
⇒The gravitational force of attraction can be given by:
The magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
In the question it is said the gravitational force is quadrupled.
Thus, the distance will be half.
It can be shown as:
[tex]F'=\frac{G*m_1*m_2}{(D/2)^2} \\\\F'=4 *\frac{G*m_1*m_2}{D}\\\\F'=4F[/tex]
Learn more:
brainly.com/question/7746145
