A hammer taps on the end of a 4.00-m-long metal bar at room temperature. a microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. the pulses are separated in time by 1 1.0 ms. what is the speed of sound in this metal?

Length that is distance s = 4.00m
Speed of sound in air V = 343 m/s
Time for metal = 11.0ms = 0.011
Calculating the time t = s / V = 4 / 343 = 0.01166s
Time for the sound in the metal = 0.01166 - 0.011 = 0.00066 = 6.6 x 10^-4s Speed of sound in metal Vm = 4 / 6.6 x 10^-4 = 6.060 x 10^3 m/s

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okpalawalter8 okpalawalter8 · Answer 2 · 2022-02-08T13:47:28+01:00

okpalawalter8 okpalawalter8

08-02-2022

We have that the Speed of sound in the metal is mathematically given as

V=5263.2m/s

Speed

Generally the equation for the time is mathematically given as

[tex]T=\frac{d}{v}\\\\Therefore\\\\T=\frac{4}{343}\\\\T=11.66\\\\Hence\\\\V=\frac{d}{dt}\\\\V=\frac{4.0}{11.66-10.9}[/tex]

V=5263.2m/s

For more information on Speed visit

https://brainly.com/question/7359669

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