You can spend at most $60 on beads. A bag containing red beads costs $2 per bag. A bag containing blue beads costs $3 per bag. You need more bags of blue beads than bags of red beads. Write a system of linear equations that represents the situation.

For this case, the first thing we must do is define variables.
We have then:
x: number of blue beads
y: number of red beads
We now write the inequations system:
[tex]3x + 2y \leq 60 x\ \textgreater \ y[/tex]
Answer:
a system of linear inequations that represents the situation is:
[tex]3x + 2y \leq 60 x\ \textgreater \ y[/tex]

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chisnau chisnau · Answer 2 · 2019-05-11T11:33:35+02:00

chisnau chisnau

11-05-2019

Answer:

[tex]2r+3b\leq 60[/tex]

Step-by-step explanation:

Let the number of blue beads bag be represented by = b

Let the number of red beads bags be represented by = r

A bag containing red beads costs $2 per bag. So, total price = 2r

A bag containing blue beads costs $3 per bag. So, total price = 3b

Now its given , you can spend at most $60 on beads so equation becomes:

[tex]2r+3b\leq 60[/tex]

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