carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position to the nearest tenth of a kilometer

That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km

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ahutt20 ahutt20 · Answer 2 · 2020-04-15T17:34:48+02:00

ahutt20 ahutt20

15-04-2020

Answer:

7.2 kilometers

Step-by-step explanation:

You are going to use the Pythagorean theorem which is a^2+b^2=c^2

so you will substitute in 6^2+4^2=c^2

36+16=x^2

52=x^2

square root 52=x

x=7.2

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