Agent bourne transferred classified files from the cia mainframe into his flash drive. the drive had 36.536.536, point, 5 megabytes on it before the transfer, and the transfer happened at a constant rate. after 125125125 seconds, there were 549549549 megabytes on the drive. the drive had a maximum capacity of 100010001000 megabytes. what was the speed of the transfer?

For this case, the first thing you should know is that the speed of the transfer is given by
Speed = Megabytes / time
Substituting
V = (549) / (125)
V = 4.392 mb / s
answer
the speed of the transfer was 4,392 mb / s

Answer Link

JeanaShupp JeanaShupp · Answer 2 · 2019-03-26T07:59:49+01:00

Answer: [tex]4.1\text{ megabytes per second}[/tex]

Step-by-step explanation:

Given: Initial load of megabytes in his flash drive before transfer = 36.5 MB

Final load of megabytes in his flash drive after transfer = 549 MB

The increase in load =[tex]549-36.5=512.5\ MB[/tex]

Time taken to transfer files = 125 seconds

The speed of transfer is the rate of change of load by with respect to time.

Thus, [tex]\text{speed}=\frac{\text{increase in load }}{\text{Time}}[/tex]

[tex]=\frac{512.5}{125}=4.1\text{ megabytes per second}[/tex]