Answer:
False.
Step-by-step explanation:
A pure imaginary number is a complex number that doesn't have a real part.
So, if a is a real number, and it doesn't specify that a is only equal to zero, then the expression a+bi is not a pure imaginary number, it's only a complex number. Examples of imaginary numbers are [tex]2i;3i;4i;....bi[/tex] where [tex]b\inR[/tex]
In this case, [tex]a\in R[/tex], that is, a can be [tex]0, \±1, \±2, \±3, ...[/tex]
Therefore the statement is false, because a can take any real value.
