angelaalien13
contestada

PLS HELP WILL MARK BRAINLIEST + 10 POINTS!!!!!
Find the exact real value of arcsin ([tex] \frac{ \sqrt{3} }{2} [/tex]).

A)[tex] \frac{4 \pi }{3} [/tex]
B)[tex] \pi [/tex]
C)[tex] \frac{ \pi }{6} [/tex]
D)[tex] \frac{ \pi }{3} [/tex]

Respuesta :

IssacAsimov
Let sin⁻¹([tex] \frac{ \sqrt{3} }{2} [/tex]) = x
Therefore, sin(x) = [tex] \frac{ \sqrt{3} }{2} [/tex]
x should lie in first quadrant because √3 and 2 both are positive.

Therefore, sin(x) = 60° = π/3 
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