2. A line goes through the points (9, 10) and (-3, 2).
(a) What is the slope of the line? Show your work
(b) Write the equation of the line in point-slope form. Show your work
(c) Write the equation of the line in slope-intercept form. Show your work.
A.) Slope = [tex] \frac{y2-y1}{x2-x1} [/tex] ------------------------------- Starting with Y's 2 - 10 = -8 --------------------------------------- Now X's -3 - 9 = -12 ------------------------------------------- -8/-12 Simplify 2/3 is your slope ================================================================== B.) I'm not to sure about this one so i'll just put the answer i got in case I get it incorrect =/ (8x + -12y = -48) =================================================================== C.) Using the slope we already had (2/3) we can start our equation Y = 2/3x + B ---------------------------------------------------------------------------------------- but what is B? To find B we plug in the numbers of (9,10) y=mx+b or 10=2/3 × 9+b, or solving for b: b=10-(2/3)(9). b=4. B is 4 ------------------------------------------------------------------------------ Now make your equation y = 2/3x + 4
