Respuesta :

kate200468
[tex]a= \frac{7-2}{101} = \frac{5}{101} \\\\x_1=2+a=2 \frac{5}{101}\\\\x_2=2+2a=2 \frac{10}{101}\\\\x_3= 2+3a=2 \frac{15}{101}\\\\....\\\\x_{98}=7-3a=7- \frac{15}{101}=6 \frac{86}{101}\\\\x_{99}=7-2a=7- \frac{10}{101}=6 \frac{91}{101}\\\\x_{100}=7-a=7- \frac{5}{101}=6 \frac{96}{101}[/tex]
AL2006
My view is that between any two rational numbers, there are
an infinite number of other rational numbers.

That's my view and I'm sticking to it.
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