A line passes through point A(12,18)A(12,18). A second point on the line has an x-value that is 125% of the x-value of point AA and a y-value that is 75% of the y-value of point AA. Use point AA to write an equation of the line in point-slope form.

An equation is y− = x(x−__).

Let's find the coordinates of the second point.

x-coordinate: 1.25*12 = 15
y-coordinate: 0,75*18 = 13.5

The points are (12,18) and (15,13.5). Next, let's determine the slope, m.

m = Δy/Δx = (13.5 - 18)/(15 - 12) = -1.5

Then, we use the form of the point-slope formula: y = mx + b. Find b using point (12,18)

18 = (-1.5)(12) + b
Solving for b,
b = 36

Therefore, the equation is: y = -1.5x +36

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bh0742901 bh0742901 · Answer 2 · 2021-02-19T19:24:42+01:00

bh0742901 bh0742901

19-02-2021

Answer:

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A line passes through point A(12,18)A(12,18). A second point on the line has an x-value that is 125% of the x-value of point AA and a y-value that is 75% of the y-value of point AA. Use point AA to write an equation of the line in point-slope form. An equation is y− __ =__ x(x−__).

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A line passes through point A(12,18)A(12,18). A second point on the line has an x-value that is 125% of the x-value of point AA and a y-value that is 75% of the y-value of point AA. Use point AA to write an equation of the line in point-slope form.

An equation is y− = x(x−__).