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Two cars are traveling in the same direction. The first car is going 40 mi/h, and the second car is going 55 mi/h. The first car left 3 hours before the second car. Which equation could you solve to find how many hours it will take for the second car to catch up to the first car? A:55t +3= 40t, B: 55t+165=40t, C: 40t+3= 55t, D:40t+120= 55t
plz show your work

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violetmarie
c. because the first car is going 40 mph and left 3 hour before the second. so itd be 40t+3 and the other car is going 55 mph sk thatd be 55t. yourr trying to figure out how long itll be until they catch up so you ewual them to each other. the answer it 40t+3=55t

The equation one can use to find how many hours it will take for the second car to catch up to the first car is 40t + 120 = 55t

The first car is going 40 mi/h

The second car is going 55 mi/h

The both cars covered the same distance.

Let

The time the second car left  = t

speed = distance / time

Therefore,

distance = speed × time

first car distance = 40 (t + 3)

second car distance = 55t

Therefore, the equation you can use to find how many hours it will take for the second car to catch up to the first car is as follows;

40 (t + 3) = 55t

40t + 120 = 55t

learn more here: https://brainly.com/question/3711300?referrer=searchResults

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