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What are the domain restrictions of the expression h^2+3h−10/h^2−12h+20 ?

Select each correct answer.

h≠10

h≠5

h≠2

h≠−5

h≠−10

h≠−2

Respuesta :

the denominator cannot be 0, so if h^2-12h+20=0
(h-2)(h-10)=0
h=2 or h=10
So h cannot be 2 or 10, the first and third choices are correct.
pemanuel

Answer:

h≠10.

Step-by-step explanation:

The expression is

[tex]\frac{h^2+3h-10}{h^2-12h+20}.[/tex]

To find the restrictions we can factor the numerator and the denominator by searching two numbers that multiplied are -10 and subtracted are 3, also for the denominator:

[tex]\frac{h^2+3h-10}{h^2-12h+20}= \frac{(h+5)(h-2)}{(h-10)(h-2)} = \frac{(h+5)}{(h-10)}.[/tex]

When we have a fraction the denominator can not be zero. Then, for our expression h needs to be different to 10 or the denominator would be zero.

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