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Consider the compound Pb(CO3)2 and answer the following questions:
a.Whats the name of the compound?
b.What is the molar mass of this compound? Explain how you calculated this value

Respuesta :

a) Lead(IV) Carbonate
b) 327.16

207.2 g + (12.01g + (15.99 x 3) ) x2 = 327.16 g

Dejanras

a) Answer is: he name of the compound is lead(IV) carbonate.

In this compound, lead has oxidation number +4 and carbonate has oxidation number -2.

b) Answer is:  the molar mass of this compound is 327.2 g/mol.

M(Pb(CO₃)₂) = Ar(Pb) + 2Ar(C) + 6Ar(O) · g/mol.

M(Pb(CO₃)₂) = 207.2 + 2 · 12 + 6 · 16 · g/mol.

M(Pb(CO₃)₂) = 327.2 g/mol.

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