To solve the problem we must know about Trigonometric functions.
Trigonometric functions
[tex]Sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
The kite is 61.08 m high above Brian’s head.
Given to us
- the angle of elevation to the kite measures 70°, ∠A = 70°
- Brian’s kite is flying above a field at the end of 65m of string, AB = 65 m
Height of the kite
In ΔABC
[tex]Sin \theta = \dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]Sin (\angle A)= \dfrac{BC}{AC}\\\\Sin (70^o)= \dfrac{BC}{65}\\\\BC = Sin (70^o)\times{65}\\\\BC = 61.08\ m[/tex]
Hence, the kite is 61.08 m high above Brian’s head.
Learn more about Trigonometric functions:
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