Two containers, A and b begin with equal volumes of liquid. 120 mL is then poured from a to B. Container b now contains four times as much liquid as A. Find the volume of liquid left in container a at the end

If n is used as the initial amount of liquid in both A and B:

4(n-120) = n+120
4n-480 = n+120
3n = 600
n = 200

Each container originally held 200ml. Container A now has 80ml and Container B has 320ml

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stokholm stokholm · Answer 2 · 2019-03-10T06:05:47+01:00

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose A and B , both has initial volume, say x

120 ML is poured from B to A, then new volumes of A and B will be:

new volume of A [tex]= (x-120)[/tex]

new volume of B [tex]= (x+120)[/tex]

Volume of B is now four times volume of A, then

[tex](x+120) = 4 (x-120)[/tex]

[tex](x+120) = 4x-480[/tex]

[tex]3x = 600[/tex]

[tex]x = 200[/tex]

So, the initial volume of A and B containers is 200

So, at the end, volume of container A = [tex]200-120= 80 [/tex]

Hence the answer is 80 : Answer

Hope it will help :)