Answer:
The coefficient of friction is 0.52
Explanation:
Weight of the box, W = N = 150 N
The force required to pull the box at a steady rate is 78 N, F = 78 N
In horizontal direction, the net force acting on the box is given by :
[tex]F-\mu N=0[/tex]
[tex]F=\mu N[/tex]
[tex]\mu=\dfrac{F}{N}[/tex]
[tex]\mu=\dfrac{78}{150}[/tex]
[tex]\mu=0.52[/tex]
So, the coefficient of friction is 0.52. Hence, this is the required solution.
