Answer:
Force, F = 9800 N
Explanation:
It is given that,
The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m
The compression in the spring, x = 25 cm = 0.25 m
To find,
The force applied to the scale by the car.
Solution,
The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :
[tex]F=-kx[/tex]
[tex]F=39200\times 0.25[/tex]
F = 9800 N
So, the force applied to the scale by the car is 9800 N.
