just to remove ambiguities, the bar over the expression means it's repeating itself to infinity.
[tex]\bf 2.888\overline{8}\impliedby \textit{now say, let's make }x=2.888\overline{8}
\\\\\\
\textit{and multiply it by 10, to move over the 8 to the left}
\\\\\\
\begin{array}{llll}
10x&=&10\cdot 2.888\overline{8}\\
&&28.88\overline{8}\\
&&26+2.888\overline{8}\\
&&26+x
\end{array}\implies 10x=26+x
\\\\\\
9x=26\implies x=\cfrac{26}{9}[/tex]
notice, the idea being, you multiply it by 10 at some power, so that you move the "recurring decimal" to the other side of the point, and then split it with a digit and "x".
now, you can plug that in your calculator, to check what you get.
