Please explain and solve!!! You won't get points unless you explain!!!

The area of the rectangle is greater than 60 square feet. Write and solve an inequality to find the possible solutions of x. Draw and correctly label the sides as follows: one side is 12 ft and one side is (2x-3) ft.

Area of a rectangle of length L and width W is A = LW.

Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.

60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.

Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.

Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.

The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)

Please explain and solve!!! You won't get points unless you explain!!! The area of the rectangle is greater than 60 square feet. Write and solve an inequality to find the possible solutions of x. Draw and correctly label the sides as follows: one side is 12 ft and one side is (2x-3) ft.

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Please explain and solve!!! You won't get points unless you explain!!!

The area of the rectangle is greater than 60 square feet. Write and solve an inequality to find the possible solutions of x. Draw and correctly label the sides as follows: one side is 12 ft and one side is (2x-3) ft.