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What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in the box.

Respuesta :

sqdancefan

Answer:

  [tex]\boxed{90}\,\text{units$^2$}[/tex]

Step-by-step explanation:

The sides AB and CD are parallel to the x-axis and 5 units apart. The length of side AB is 6-(-12) = 18 units. The area is the product of these dimensions:

  Area = (Base)(Height) = (18 units)(5 units) = 90 units²

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