Answer:
Equation of line , 5x + 3y = 0
Step-by-step explanation:
The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Here points are given by (-3,0) and (-6,5)
Slope[tex]=\frac{5-0}{(-6)-(-3)}=\frac{-5}{3}[/tex]
The slope of parallel lines are same. So slope of required line [tex]=\frac{-5}{3}[/tex]
Equation of a line with slope m passing through origin is given by
y =mx
So equation of line, [tex]y=\frac{-5}{3}x\\\\3y=-5x\\\\5x+3y=0[/tex]
Equation of line , 5x + 3y = 0
