John bikes 22km per hour and starts at mile 10. Gwynn bikes 28 km per hour and starts at mile 0. Which system of linear equations represents this situation?

If j is the distance in km John reaches after time t hours, and g is the same for Gwynn, the equations are
j=10+22t and g=28t.
If x is the distance at which they meet the equations form a system from which t, when they meet, can be calculated: 10+22t=28t, 6t=10, t=5/3=1 hour 40 minutes. And they meet at 28×5/3=10+22×5/3=46.67km.

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ApusApus ApusApus · Answer 2 · 2019-04-25T07:03:56+02:00

Answer:

[tex]d=22t+10...(1)[/tex]

[tex]d=28t...(2)[/tex]

Step-by-step explanation:

Let t represent the number of hours and d represent the total distance after t hours.

We have been given that John bikes 22 km per hour and starts at mile 10. This means that slope of line will be 22 and y-intercept will be 10. So total distance covered by John in t hours will be:

[tex]d=22t+10...(1)[/tex]

We are also told that Gwynn bikes 28 km per hour and starts at mile 0. This means that slope of line will be 28 and y-intercept will be 0. So total distance covered by Gwynn in t hours will be:

[tex]d=28t+0[/tex]

[tex]d=28t...(2)[/tex]

Therefore, our required system of linear equations will be:

[tex]d=22t+10...(1)[/tex]

[tex]d=28t...(2)[/tex]