According to the question,
The initial velocity will be:
→ [tex]v^2 = u^2 +2 ah[/tex]
or,
→ [tex]u = \sqrt{v^2 - 2gh}[/tex]
By substituting the values, we get
[tex]= \sqrt{(0)^2-2(-9.8)(2.8)}[/tex]
[tex]= 7.41 \ m/s[/tex]
Now,
The time of ascent will be:
→ [tex]v = u+at[/tex]
or,
→ [tex]t = \frac{v-u}{-g}[/tex]
[tex]= \frac{0-7.41}{-9.8}[/tex]
[tex]= 0.756 \ s[/tex]
hence,
The total time will be:
→ [tex]t_{tot} = 0.756+0.756[/tex]
[tex]= 1.51 \ s[/tex]
Thus the above response is right.
Learn more about vertical height here:
https://brainly.com/question/5763014
