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A gray kangaroo can bound across a fl at stretch of ground 810 with each j ump can-ying it 10 m from the takeoff point. if the kangaroo leaves the ground at a 20° angle, what are its (a) takeoff speed and (b) horizontal speed?

Respuesta :

The formula for maximum distance is 
X = (V^2 / g) * sin (2 * theta) 
10 = (V^2 / 9.8) * sin (2 * 20) 
10 = (V^2 / 9.0) * sin(40) 
10 = (V^2 / 9.8) * 0.324 
v^2 = (10 / 0.324) * 9.8 
V^2 = 302.47
v = 17.39 meters/sec (takeoff speed) 

The horizontal speed is  = Takeoff Speed * Cos(20) = 17.39 * 0.910 = 16.341 meters / sec 
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