A graduated cylinder contains 15.75 mL of water. A metal that weighs 31.745 g is added. The final reading is 38.55 mL. Using the correct number of significant figures, determine the density of the metal = _____ g/mL First Determine Volume of Metal: Report result to the same number of decimal places as the number with the least number of decimal places. Use this volume in calculation. Second Determine Density of metal: D=M/V Report result to the same number of significant figures as the number with the least number of significant figures. Do not use exponential notation in answer.

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znk znk · Answer 1 · 2015-09-19T04:18:03+02:00

V = 38.55 mL - 15.75 mL = 22.80 mL = 22.80 cm³

D = [tex] \frac{M}{V} [/tex] = [tex] \frac{31.745 g}{ 22.80 cm^{3} } [/tex] = 1.392 g/cm³

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aliasger2709 aliasger2709 · Answer 2 · 2022-06-09T08:19:36+02:00

The density of the substance is given by the mass and the volume. The density of the metal weighing 31.745 gms is 1.392 g/cm³.

The density of the substance is grams of the substance per cubic centimeter of the solution.

Given,

Mass of metal = 31.745 gms

Volume = 38.55 mL - 15.75 mL = 22.80 mL

The volume is converted from mL to cm³:

1 mL = 1 cm³

22.80 mL = 22.80 cm³

Density (D) is calculated as:

D = M ÷ V

= 31.745 ÷ 22.80

= 1.392 g/cm³

Therefore, the density of the metal is 1.392 g/cm³.

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