Respuesta :
[tex]|3x+12|=18\iff3x+12=18\ or\ 3x+12=-18\\subtract\ 12\ from\ both\ sides\\\\3x=6\ or\ 3x=-30\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\huge\boxed{x=2\ or\ x=-10}[/tex]
|3x+12|=18
Solve Absolute Value.
|3x+12|=18
3x+12=18 or 3x+12=−18
3x+12=18(Possibility 1)
3x+12−12=18−12(Subtract 12 from both sides)
3x=6
3x3=63(Divide both sides by 3)
x=2
3x+12=−18(Possibility 2)
3x+12−12=−18−12(Subtract 12 from both sides)
3x=−30
3x3=−303(Divide both sides by 3)
x=−10
The answer is:
x=2 or x=−10
Solve Absolute Value.
|3x+12|=18
3x+12=18 or 3x+12=−18
3x+12=18(Possibility 1)
3x+12−12=18−12(Subtract 12 from both sides)
3x=6
3x3=63(Divide both sides by 3)
x=2
3x+12=−18(Possibility 2)
3x+12−12=−18−12(Subtract 12 from both sides)
3x=−30
3x3=−303(Divide both sides by 3)
x=−10
The answer is:
x=2 or x=−10
