The measured data is
x=[10.56, 9.52, 9.73, 9.80, 9.78, 10.91].
Calculate the mean.
m = (10.56+9.52+9.73+9.80+9.78+10.91)/6 = 10.05
Calculate the deviations from the mean.
k = x - m
= [0.51, -0.53, -0.32, -0.25, -0.27, 0.86]
Calculate the absolute deviation from the mean.
[tex]d= \frac{1}{6} | (0.51-0.53-0.32-0.25-0.27+0.86) | = |1.184\times10^{-15}| \approx 0[/tex]
Answer: 0
