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beanthemachine
Well, since the expanded form of (x-2)^4 is x^4-8x³+24x²-32x+16

The constant is the 4th term, since it is the integer so your answer is 16.
Panoyin
(x - 2)⁴
(x - 2)²(x - 2)²
(x - 2)(x - 2)(x - 2)(x - 2)
(x(x) - x(2) - 2(x) + 2(2))(x(x) - x(2) - 2(x) + 2(2))
(x² - 2x - 2x + 4)(x² - 2x - 2x + 4)
(x² - 4x + 4)(x² - 4x + 4)
x²(x² - 4x + 4) - 4x(x² - 4x + 4) + 4(x² - 4x + 4)
x²(x²) - x²(4x) + x²(4) - 4x(x²) + 4x(4x) - 4x(4) + 4(x²) - 4(4x) + 4(4)
x⁴ - 4x³ + 4x² - 4x³ + 16x² - 16x + 4x² - 16x + 16
x⁴ - 4x³ - 4x³ + 4x² + 16x² + 4x² - 16x - 16x + 16
x⁴ + 8x³ + 24x² - 32x + 16

The constant term in the expansion of the binomial is 16.
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