When factored completely, the expression p^4 - 81 is equivalent to
(1) (p^2 + 9)(p^2 - 9)
(2) (p^2 - 9)(p^2 - 9)
(3) (p^2 + 9)(p + 3)(p - 3)
(4) (p + 3)(p - 3)(p + 3)(p - 3)

p⁴ - 81
p⁴ + 9p² - 9p² - 81
p²(p²) + p²(9) - 9(p²) - 9(9)
p²(p² + 9) - 9(p² + 9)
(p² - 9)(p² + 9)
(p² + 3p - 3p - 9)(p² + 9)
(p(p) + p(3) - 3(p) - 3(3))(p² + 9)
(p(p + 3) - 3(p + 3))(p² + 9)
(p - 3)(p + 3)(p² + 9)

The answer is (3).

Answer Link

calculista calculista · Answer 2 · 2018-08-14T13:43:57+02:00

calculista calculista

14-08-2018

we have

[tex] p^4 - 81 [/tex]

we know that

[tex] (a^{2} -b^{2} )=(a+b)(a-b) [/tex]

so

[tex] (p^4 - 81)=(p^{2} +9)(p^{2} -9) [/tex] ------> expression [tex] 1 [/tex]

and

[tex] (p^{2} -9)=(p +3)(p-3) [/tex] ------> expression [tex] 2 [/tex]

Substitute expression [tex] 2 [/tex] in expression [tex] 1 [/tex]

[tex] (p^4 - 81)=(p^{2} +9)(p+3)(p-3) [/tex]

therefore

the answer is the option

[tex] (p^{2} +9)(p+3)(p-3) [/tex]

Answer Link

When factored completely, the expression p^4 - 81 is equivalent to (1) (p^2 + 9)(p^2 - 9) (2) (p^2 - 9)(p^2 - 9) (3) (p^2 + 9)(p + 3)(p - 3) (4) (p + 3)(p - 3)(p + 3)(p - 3)

Respuesta :

Otras preguntas

When factored completely, the expression p^4 - 81 is equivalent to
(1) (p^2 + 9)(p^2 - 9)
(2) (p^2 - 9)(p^2 - 9)
(3) (p^2 + 9)(p + 3)(p - 3)
(4) (p + 3)(p - 3)(p + 3)(p - 3)