mholtlawoffice mholtlawoffice

18-04-2024
Mathematics

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find the zeros of thr function f (x)(x-2)^2 -9

find the zeros of thr function f xx22 9 class=

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aguileracapote aguileracapote

18-04-2024

Answer:

-4.449

4.449

Step-by-step explanation:

[tex](x-2)^2-9=0\\x^2-4x+4-9=0\\x^2-4x-2=0\\\frac{4+-\sqrt{4^2-4*1*(-2)} }{2*1} \\\frac{4-\sqrt{24} }{2}=-4.449\\\frac{4+\sqrt{24} }{2}=4.449\\[/tex]

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