Answer:
The lead ball
Step-by-step explanation:
First, calculate the volume of the spheres:
[tex]v=\frac{4}{3}\pi (r)^3=\frac{4}{3}\pi (1.2)^3=7.24 cm^3[/tex]
Then, multiply this value by the densities of aluminum and lead.
Aluminum:
[tex]W_A_l=2.7g/cm^3*7.24cm^3=19.55g[/tex]
Lead:
[tex]W_P_b=11.34g/cm^3*7.24cm^3=82.1g[/tex]
The lead sphere is about 62 grams heavier.
