First lets find the time it took to get there
Distance = Speed * time
720 = 295 * t
t = 720/295 = 2.440678
We can now find the time of the return flight
5 - t is the time of the return flight
5 - 2.440678 = 2.559322
distance = speed * time (we can now find the speed
720 = speed * 2.559322
speed = 720/2.559322
speed = 281.3245 mph
therefore the wind on the return trip reduce the original speed and was a head wind
295 - 281.3245 = 13.6755 mph (head wind
Answer:
