Answer:
A+B+C=7+21+28= 56cents.
Step-by-step explanation:
Let's represent the amounts of \( A \), \( B \), and \( C \) in cents as \( a \), \( b \), and \( c \) respectively.
Given that the ratio of \( A \) to \( B \) to \( C \) is \( 1:3:4 \), we can express \( a \), \( b \), and \( c \) in terms of this ratio.
Let \( x \) be the common multiple of the ratio parts, so:
- \( a = 1x \)
- \( b = 3x \)
- \( c = 4x \)
We're also given that \( c = 28 \) cents. Substituting this value into the expression for \( c \):
\[ 4x = 28 \]
Now, we can solve for \( x \):
\[ x = \frac{28}{4} = 7 \]
Now that we have the value of \( x \), we can find the values of \( a \), \( b \), and \( c \):
- \( a = 1 \times 7 = 7 \) cents
- \( b = 3 \times 7 = 21 \) cents
- \( c = 4 \times 7 = 28 \) cents
The sum of \( A \), \( B \), and \( C \) is:
\[ A + B + C = 7 + 21 + 28 = \boxed{56} \] cents.
