Answer:
log7(2 ⋅ 6) + log73 is equal to log7(36).
Step-by-step explanation:
To expand log412, we can use the product property:
log412 = log44 + log43
Since log43 is given as approximately 0.792:
log44 + 0.792 = 2 + 0.792 = 2.792
Therefore, log412 is equal to 2.792.
To write log7(2 ⋅ 6) + log73 as a single log, we can combine the two logarithms using the product property:
log7(2 ⋅ 6) + log73 = log7(12) + log7(3)
Next, we can combine the two terms into a single logarithm using the product property:
= log7(12 ⋅ 3)
Therefore, log7(2 ⋅ 6) + log73 is equal to log7(36).
