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How much work did a horse do that pulled a 200 kg wagon 50 km without acceleration along a level road if the effective coefficient of friction was 0.600?

Respuesta :

MathPhys

Answer:

58.8 MJ

Explanation:

Since there is no change in speed or elevation, work = friction force × distance.

W = Fd

W = mgμ d

W = (200 kg) (9.8 m/s²) (0.600) (50,000 m)

W = 58,800,000 J

W = 58.8 MJ

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