Mikal's leg angularly accelerates 3000°/s² around her hip joint during a roundhouse kick in the transverse plane. The moment of inertia of her leg around the axis of rotation for this kick is 0.75 kg.m². How large is the torque that produces this acceleration?

Respuesta :

Answer: 39.27 Nm

Explanation:

To find the torque (τ) that produces this angular acceleration (α) for Mikal's leg, we can use the formula:

τ = I×α, where:

  • τ is the torque (in Newton-meters, Nm)
  • I is the moment of inertia (in kg.m²)
  • α is the angular acceleration (in radians per second squared, rad/s²)

First, we need to convert the angular acceleration from degrees per second squared (°/s² ) to radians per second squared:

3000°/s² × (π/180)

= 3000 × (π/180) rad/s²

= 52.35987755 rad/s²

Now, we can use the formula to calculate the torque:

τ = 0.75 × 52.35987755

τ = 39.27 Nm

The torque is 39.27 Nm.

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