Answer:
[tex]8[/tex]
Step-by-step explanation:
[tex]\text{Let the required number be }x.\\\text{According to question,}\\7\times\text{Number}-16=5\times\text{Number}\\\text{or, }7x-16=5x\\\text{Subtracting }'5x'\text{ from both sides,}\\\text{}\quad7x-5x-16=5x-5x\\\text{or, }2x-16=0\\\text{Adding }'16'\text{ on both sides,}\\\text{}\quad 2x-16+16=0+16\\\text{or, }2x=16[/tex]
[tex]\text{Dividing by }'2'\text{ on both sides,}\\\\\dfrac{2x}{2}=\dfrac{16}{2}\\\\\text{or, }x=8[/tex]
[tex]\text{So the number is 8.}[/tex]
