Answer:
7 Hz
Explanation:
The number of beats per second (or beat frequency) heard when two tuning forks are sounded simultaneously is equal to the absolute difference in their frequencies. Given that one tuning fork has a frequency of 245 Hz and the other has a frequency of 238 Hz, the formula to find the number of beats per second is:
[tex]\boxed{\begin{array}{ccc}\text{\underline{Beat Frequency}:} \\\\ f_{\text{beats}} = \big|f_1 - f_2\big| \\\\\text{Where:} \\\quad f_{\text{beats}} \ \text{is the beat frequency (beats per second)} \\\quad f_1 \ \text{and} \ f_2 \ \text{are the frequencies of the two sound waves}\end{array}}[/tex]
Plug in our values and solve:
[tex]\Longrightarrow f_{\text{beats}} = \big|245 \text{ Hz} - 238 \text{ Hz}\big|\\\\\\\\\Longrightarrow f_{\text{beats}} = \big|7 \text{ Hz}\big|\\\\\\\\\therefore f_{\text{beats}} = \boxed{ 7 \text{ Hz}}[/tex]
Thus, when the two tuning forks are sounded simultaneously, 7 beats per second are heard.
When two tuning forks with frequencies of 245 Hz and 238 Hz are sounded together, they produce a beat frequency of 7 beats per second.
When two tuning forks having different frequencies are sounded simultaneously, they produce a phenomenon known as beats.
The beat frequency is determined by calculating the absolute difference between the two frequencies. In this case, we have tuning forks with frequencies of 245 Hz and 238 Hz.
To find the number of beats per second, we subtract the smaller frequency from the larger frequency:
Beat frequency = |245 Hz - 238 Hz|
= 7 Hz
Therefore, when you sound these two tuning forks together, you will hear 7 beats per second.
